| Answer
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| n | At position B
the total energy |
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| still has to be
137.3J because |
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| energy is
conserved and |
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| because there
is no friction no |
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| energy was
“lost” along the |
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| slide |
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| n | So….ET(position
B)=137.3J=0J+KE |
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| n | So…KE also
equals 137.3J at |
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| position B |
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| n | More… |
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