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n |
2.) Since
position #2 is half
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way down total
energy will be
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half in PE and
half in KE
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n |
So…KE at
position #2 will be
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half that at
position #3
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n |
So…KE at
position #2 is
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78.125J
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n |
Then use KE (at
#2)=78.125J
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=1/2 x 0.5kg x v2
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n |
v=17.68m/s at
position #2
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